\u0410\u0440\u0438\u0444\u043c\u0435\u0442\u0438\u043a\u0438\u0439\u043d \u0434\u0443\u043d\u0434\u0430\u0436<\/span><\/strong><\/span><\/p>\n $$<a> = \\frac{a_1 + a_2 + a_3 + \\dots + a_n}{n} = \\frac{\\sum_{i=1}^n a_i}{n}$$<\/span><\/span><\/p>\n \u0413\u0435\u043e\u043c\u0435\u0442\u0440\u0438\u0439\u043d \u0434\u0443\u043d\u0434\u0430\u0436:<\/span><\/span><\/strong><\/p>\n $$s = (a_1 \\cdot a_2 \\cdot a_3 \\dots a_n)^{1\/n}$$<\/span><\/span><\/p>\n \u04ae\u0440\u0436\u0432\u044d\u0440 \u043d\u0438\u0439\u043b\u0431\u044d\u0440\u0438\u0439\u043d \u0442\u043e\u043c\u044a\u0451\u043e\u043d\u0443\u0443\u0434<\/span><\/strong><\/span><\/p>\n $$a(b+c)=ab+ac$$<\/span><\/span><\/p>\n $$(a+b)^2 = a^2 + 2ab + b^2$$<\/span><\/span><\/p>\n $$(a-b)^2 = a^2 – 2ab + b^2$$<\/span><\/span><\/p>\n $$(a+b)(a-b)=a^2 – b^2$$<\/span><\/span><\/p>\n $$(a+b)^3 = a^3 + 3a^2 b + 3a b^2 + b^3$$<\/span><\/span><\/p>\n $$(a-b)^3 = a^3 – 3a^2 b + 3a b^2 – b^3$$<\/span><\/span><\/p>\n $$a^3 + b^3 = (a+b)(a^2 – ab + b^2)$$<\/span><\/span><\/p>\n $$a^3 – b^3 = (a – b)(a^2 + ab + b^2)$$<\/span><\/span><\/p>\n \u041d\u044c\u044e\u0442\u043e\u043d\u044b \u0431\u0438\u043d\u043e\u043c:<\/span><\/strong><\/span><\/p>\n $$(x+y)^n = C_0^n x^n + C_1^n x^{n-1} y + \\cdots + C_k^{n} x^{n-k} y^k + \\cdots + C_{n-1}^n x y^{n-1} + C_n^n y^n$$<\/span><\/span><\/p>\n \u0411\u0443\u0442\u0430\u0440\u0445\u0430\u0439\u043d \u0448\u0438\u043d\u0436 \u0447\u0430\u043d\u0430\u0440<\/strong><\/span> $$ \\frac{A}{B} = \\frac{-A}{-B}$$<\/span><\/span><\/p>\n $$ \\frac{A_1}{B_1} \\cdot \\frac{A_2}{B_2} = \\frac{A_1 A_2}{B_1 B_2} $$<\/span><\/span><\/p>\n $$ \\big( \\frac{P}{Q} \\big) ^n = \\frac{P^n}{Q^n}$$<\/span><\/span><\/p>\n $$\\frac{P_1}{Q_1} \\div \\frac{P_2}{Q_2} = \\frac{P_1}{Q_1} \\cdot \\frac{Q_2}{P_2}\\$$<\/span><\/span><\/p>\n \u0417\u044d\u0440\u0433\u0438\u0439\u043d \u0448\u0438\u043d\u0436 \u0447\u0430\u043d\u0430\u0440<\/span><\/strong><\/span><\/p>\n $$a^n \\cdot a^k = a^{n+k}$$<\/span><\/span><\/p>\n $$\\frac{a^n}{a^k} = a^{n-k}$$<\/span><\/span><\/p>\n $$(a^n)^k = a^{nk}$$<\/span><\/span><\/p>\n $$a^n \\cdot b^n = (ab)^n$$<\/span><\/span><\/p>\n $$\\frac{a^n}{b^n} = \\big( \\frac{a}{b} \\big)^n$$<\/span><\/span><\/p>\n $$a^{-n} = \\frac{1}{a^n}$$<\/span><\/span><\/p>\n $$!{\\big( \\frac{a}{b} \\big)^{-n} = \\big( \\frac{b}{a}} \\big)^{n}$$<\/span><\/span><\/p>\n \u042f\u0437\u0433\u0443\u0443\u0440\u044b\u043d \u0448\u0438\u043d\u0436 \u0447\u0430\u043d\u0430\u0440:<\/span><\/strong><\/span><\/p>\n $$a^{1\/n} = \\sqrt[n]{a}$$<\/span><\/span><\/p>\n $$\\sqrt[n]{ab}= \\sqrt[n]a \\cdot \\sqrt[n]b$$<\/span><\/span><\/p>\n $$\\sqrt[n]{\\frac{a}{b}} = \\frac{\\sqrt[n]a} {\\sqrt[n]b} $$<\/span><\/span><\/p>\n $$(\\sqrt[n]a)^k = \\sqrt[n]{a^k}$$<\/span><\/span><\/p>\n $$a^{\\frac{m}{n}} = \\sqrt[n]{a^m}$$<\/span><\/span><\/p>\n $$\\sqrt[n]{\\sqrt[k]a} = \\sqrt[nk]{a}$$<\/span><\/span><\/p>\n \u041b\u043e\u0433\u0430\u0440\u0438\u0444\u043c\u044b\u043d \u0447\u0430\u043d\u0430\u0440<\/span><\/strong><\/span><\/p>\n $$\\log_a 1 = 0$$<\/span><\/span><\/p>\n $$\\log_a a = 1$$<\/span><\/span><\/p>\n $$a^{\\log_a x} = x$$<\/span><\/span><\/p>\n $$\\log_a({x_1 x_2}) = \\log_a x_1 + \\log_a x_2$$<\/span><\/span><\/p>\n $$\\log_a(\\frac{x_1}{x_2}) = \\log_a x_1 – \\log_a x_2$$<\/span><\/span><\/p>\n \u0425\u044d\u0440\u044d\u0432 x>0 \u0431\u043e\u043b \u0434\u0430\u0440\u0430\u0430\u0445 \u0447\u0430\u043d\u0430\u0440\u0443\u0443\u0434 \u0445\u04af\u0447\u0438\u043d\u0442\u044d\u0439<\/span><\/span><\/p>\n $$\\log_a x^r = r \\cdot \\log_a x$$<\/span><\/span><\/p>\n $$\\log_a x = \\frac{\\log_b a}{\\log_b x}$$<\/span><\/span><\/p>\n $$\\log_a x = \\log_{a^k}{x^k}$$<\/span><\/span><\/p>\n \u0421\u044d\u043b\u0433\u044d\u043c\u044d\u043b:<\/span><\/strong><\/span><\/p>\n $$C_n^k = \\frac{n!}{k!(n-k)!}$$<\/span><\/span><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" \u0410\u0440\u0438\u0444\u043c\u0435\u0442\u0438\u043a\u0438\u0439\u043d \u0434\u0443\u043d\u0434\u0430\u0436 $$<a> = \\frac{a_1 + a_2 + a_3 + \\dots + a_n}{n} = \\frac{\\sum_{i=1}^n a_i}{n}$$ \u0413\u0435\u043e\u043c\u0435\u0442\u0440\u0438\u0439\u043d \u0434\u0443\u043d\u0434\u0430\u0436: $$s = (a_1 \\cdot a_2 \\cdot a_3 \\dots a_n)^{1\/n}$$ \u04ae\u0440\u0436\u0432\u044d\u0440 \u043d\u0438\u0439\u043b\u0431\u044d\u0440\u0438\u0439\u043d \u0442\u043e\u043c\u044a\u0451\u043e\u043d\u0443\u0443\u0434 $$a(b+c)=ab+ac$$ $$(a+b)^2 = a^2 + 2ab + b^2$$ $$(a-b)^2 = a^2 – 2ab + b^2$$ $$(a+b)(a-b)=a^2 – b^2$$ $$(a+b)^3 = a^3 + 3a^2 b +… Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":713,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-380","page","type-page","status-publish","hentry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/pages\/380","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/soniuch.net\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=380"}],"version-history":[{"count":0,"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/pages\/380\/revisions"}],"up":[{"embeddable":true,"href":"https:\/\/soniuch.net\/index.php?rest_route=\/wp\/v2\/pages\/713"}],"wp:attachment":[{"href":"https:\/\/soniuch.net\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=380"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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\n$$ \\frac{A}{B} = \\frac{AC}{BC}$$<\/span><\/span><\/p>\n
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